WebDec 20, 2024 · The formula for the number of binary bits required to store n integers (for example, 0 to n - 1) is: log e (n) / log e (2) and round up. For example, for values -128 to … WebJun 3, 2016 · 4096/128 = num lines 4096/128/4 = 8 = num sets (each set is 4 lines in 4-way set assoiative) So, need 3 bits to choose set (2^3=8) We have 16-3 = 13 bits left for the tag and word. Because the question says that memory is byte addressable, I think that this means that the word is 8 bits (= 1 byte) long, and thus the tag is 16-3-8 = 5 bits long.
Convert bits to Bytes - Digital Storage Conversions (Binary)
WebDec 13, 2012 · Average Number of Bits in a d-Digit Integer. The average number of bits required for a d -digit integer is the total number of bits required to represent all d -digit integers divided by the number of d -digit … WebBit Calculator. Make conversions between all representation sizes Go. Bit Shift Calculator. Shift bits on a number Go. Binary Calculator. Make calculations like addition and … pool bros houston
BITRSHIFT function - Microsoft Support
WebTo convert decimal to binary is also very simple, you simply divide the decimal value by 2 and then write down the remainder. Repeat this process until you cannot divide by 2 anymore, for example let's take the decimal … WebMar 13, 2024 · 1 Answer. Sorted by: 3. Calculate the size of each address in m bits. If main memory has 2048 bytes, then we have 2048=2^m unique addresses. This can be calculated as log2 (2048) = 11 bits per address. (2^11=2048) Calculate bit offset n from the number of bytes in a block. 64 bytes/8 blocks = 8 bytes per block. 2^n=8, or log2 (8). WebWe can now represent twice as many values: the values we could represent before with a 0 appended and the values we could represent before with a 1 appended. So the the number of values we can represent with n bits is just 2^n (2 to the power n) The thing you are missing is which encoding scheme is being used. shaquille o\u0027neal boys and girls club